[Clp] constant in MPS objective

[William H. Patton]

CLP interprets a constant in the objective with the opposite sign compared
to lp_solve and glpsol. I think they got it right.

NAME          ex1c   
ROWS
 N  OBJROW
 L  C1
 L  R2
COLUMNS
    x1        OBJROW    1.             C1        2.          
    x1        R2         -4.        
    x2        OBJROW     -2.           C1        1.          
    x2        R2        4.          
RHS
    RHS       OBJROW     +10.          C1        5.
    RHS       R2        5.          
ENDATA

Or 

NAME          ex1b   
ROWS
 N  OBJROW
 L  C1
 L  R2
COLUMNS
    x1        OBJROW    1.             C1        2.          
    x1        R2         -4.        
    x2        OBJROW     -2.           C1        1.          
    x2        R2        4.          
RHS
    RHS       OBJROW     -10.          C1        5.          
    RHS       R2        5.          
ENDATA

Solve oppositely to lp_solve
Clp:import ex1b.MPS
At line 1 NAME          ex1b
At line 2 ROWS
At line 6 COLUMNS
At line 11 RHS
At line 14 ENDATA
Problem ex1b has 2 rows, 2 columns and 4 elements
Model was imported from .\ex1b.MPS in 0 seconds
Clp:solve
0  Obj 10 Dual inf 2 (1)
2  Obj 6.25
Optimal - objective value 6.25
Optimal objective 6.25 - 2 iterations time 0.002
Clp:
Clp:import ex1c.MPS
At line 1 NAME          ex1c
At line 2 ROWS
At line 6 COLUMNS
At line 11 RHS
At line 14 ENDATA
Problem ex1c has 2 rows, 2 columns and 4 elements
Model was imported from .\ex1c.MPS in 0 seconds
Clp:solve
0  Obj -10 Dual inf 2 (1)
2  Obj -13.75
Optimal - objective value -13.75
Optimal objective -13.75 - 2 iterations time 0.002
Clp:

==============================================
\Jun>lp_solve -mps ex1b.mps

Value of objective function: -13.75000000

Actual values of the variables:
x1                           1.25
x2                            2.5

\Jun>lp_solve -mps ex1c.mps

Value of objective function: 6.25000000

Actual values of the variables:
x1                           1.25
x2                            2.5

\Jun>

==============================================
\glpk\glpk-4.8>glpsol ex1b.mps
lpx_read_mps: reading problem data from `ex1b.mps'...
lpx_read_mps: problem ex1b
lpx_read_mps: 3 rows, 2 columns, 6 non-zeros
lpx_read_mps: 14 cards were read
lpx_simplex: original LP has 3 rows, 2 columns, 6 non-zeros
lpx_simplex: presolved LP has 2 rows, 2 columns, 4 non-zeros
lpx_adv_basis: size of triangular part = 2
*     0:   objval = -1.000000000e+001   infeas =  0.000000000e+000 (0)
*     2:   objval = -1.375000000e+001   infeas =  0.000000000e+000 (0)
OPTIMAL SOLUTION FOUND
Time used:   0.0 secs
Memory used: 0.1M (91756 bytes)

\glpk\glpk-4.8>
\glpk\glpk-4.8>glpsol ex1c.mps
lpx_read_mps: reading problem data from `ex1c.mps'...
lpx_read_mps: problem ex1c
lpx_read_mps: 3 rows, 2 columns, 6 non-zeros
lpx_read_mps: 14 cards were read
lpx_simplex: original LP has 3 rows, 2 columns, 6 non-zeros
lpx_simplex: presolved LP has 2 rows, 2 columns, 4 non-zeros
lpx_adv_basis: size of triangular part = 2
*     0:   objval =  1.000000000e+001   infeas =  0.000000000e+000 (0)
*     2:   objval =  6.250000000e+000   infeas =  0.000000000e+000 (0)
OPTIMAL SOLUTION FOUND
Time used:   0.0 secs
Memory used: 0.1M (91756 bytes)

\glpk\glpk-4.8>

William