[Cbc] model->secondaryStatus()

[John Forrest]

Ivan,

How is the model being input?  Various formats use different defaults 
e.g. in mps format using intorg/intend a variable with no bound defined 
is 0-1.  If I then add a PL entry for x1 then cbc does say unbounded.  
If I use UP 10**n then optimal integer solution is

x1 = (10**n)-1
x2 = 4
x3 = -5*(10**(n-1))+5

John Forrest

On 21/03/13 18:40, Ivan Meireles Costa wrote:
> Hi guys,
>
> I trying to solve a small mip:
>
> Max 2 x1 + x2 - 3 x3
>
> subject to:
> r1: 2 x1 + x2 >= 4
> r2: 1 x1 + 4 x2 + 2 x3 = 5
> r3: 3 x2 + x3 <= 7
>
> x1 -> LB = 0
> x2 -> LB = 0
> x2 -> UB = 4
> x3 -> UB = 5
>
> I know it no have a optimal solution, but the 
> method model->secondaryStatus() returns 1 (1 linear relaxation not 
> feasible (or worse than cutoff) ).
> However the problem is unbounded, i expected 7 (7 linear relaxation 
> unbounded).
>
>
> Att. 	
> 	
> 	
> 					
>
>
> -- 
> *Ivan Meireles Costa*
> *Analista de** otimização*
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