[Coin-ipopt] Fortran version: lower/upper bounds

[Andreas Waechter]

Hi Ned,

Yes, your correction of the indexing description is correct.

Regards,

Andreas

On Fri, 29 Jun 2007, Ned Nedialkov wrote:

>
>
> Dear All,
>
> I am reading the description for setting lower and upper bounds on variables 
> in the Fortran version with C interface.
>
> I am puzzled by the description of bnds_l and bnds_u:
>
>   nlb:    number of lower bounds on variables
>   ilb:    indices for lower bounds (array length nlb)
>   bnds_l: values of lower bounds (array length nlb)
>              i.e. variable x[ilb[i]] has lower bound bnds_l[i] for 
> i=1,..,nlb
>   nub:    number of upper bounds on variables
>   iub:    indices for upper bounds (array length nub)
>   bnds_u: values of upper bounds (array length nub)
>              i.e. variable x[iub[i]] has upper bound bnds_u[i] for 
> i=1,..,nub
>
> in
>
> extern Ipopt DLLEXPORT Ipopt_Create(fint n, fint m, fint nlb,
> 				    fint *ilb, real *bnds_l, fint nub,
> 				    fint *iub, real *bnds_u, pEval_F Eval_F,
> 				    pEval_C Eval_C, pEval_G Eval_G,
> 				    pEval_A Eval_A, pEval_H Eval_H);
>
>
> Should the above description read
>
>   bnds_l: values of lower bounds (array length nlb)
>              i.e. variable x[ilb[i]] has lower bound bnds_l[i] for i= 
> 0,..,nlb-1
>
> and
>
>    bnds_u: values of upper bounds (array length nub)
>              i.e. variable x[iub[i]] has upper bound bnds_u[i] for 
> i=0,..,nub-1
>
> That is, the indexing is from 0 to nlb-1 and nub-1, respectively.
>
> Many thanks,
> Ned Nedialkov
>
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