[Cbc] multiple solutions with CbcMain

[Matthew Galati]

Hmm.

That didn't seem to help.

  const char * argv[20];
   int   argc      = 0;
   string cbcExe   = "cbc";
   string cbcSolve = "-solve";
   string cbcQuit  = "-quit";
   string cbcLog   = "-log";
   string cbcLogSet= UtilIntToStr(debugLevel);
   string cbcMaxSave= "-maxSaved";
   string cbcMaxSaveSet= "100";

   argv[argc++] = cbcExe.c_str();
   argv[argc++] = cbcLog.c_str();
   argv[argc++] = cbcLogSet.c_str();
   argv[argc++] = cbcMaxSave.c_str();
   argv[argc++] = cbcMaxSaveSet.c_str();
   argv[argc++] = cbcSolve.c_str();
   argv[argc++] = cbcQuit.c_str();
   CbcModel cbc(*osiClp);
   CbcMain0(cbc);
   CbcMain1(argc, argv, cbc);

Then, in the log I see:
Cbc0012I Integer solution of -264.97 found by rounding after 1 iterations
and 0 nodes (0.01 seconds)
Cbc0016I Integer solution of -282.4 found by strong branching after 11
iterations and 6 nodes (0.02 seconds)
Cbc0012I Integer solution of -282.4 found by feasibility pump after 0
iterations and 0 nodes (0.03
seconds)


But, in the end:
 int nSolutions = cbc.numberSavedSolutions();
 printf("nSolutions=%d\n", nSolutions);

nSolutions=1




On Fri, Feb 13, 2015 at 10:36 AM, Haroldo Gambini Santos <
haroldo.santos at gmail.com> wrote:

>  Hi Matthew,
>
> To call CbcMain I think that the recommended way is:
>
> CbcMain0(cbcModel);
> CbcMain1( nArgs, args, cbcModel);
>
> Using this way I got multiple solutions at the end using
>
> cbcModel.numberSavedSolutions()  and contents   cbcModel.savedSolution(i);
>
>
>
>
> On 13-02-2015 11:53, Matthew Galati wrote:
>
> I switched to CbcMain from CbcModel.branchAndBound() based on comments
> about performance.
>
>  I want to get multiple solutions from Cbc.
>
>  I am doing this:
>
>     const char * argv[20];
>    int   argc      = 0;
>    string cbcExe   = "cbc";
>    string cbcSolve = "-solve";
>    string cbcQuit  = "-quit";
>    string cbcLog   = "-log";
>    string cbcLogSet= UtilIntToStr(debugLevel);
>    string cbcMaxSave= "-maxSaved";
>     string cbcMaxSaveSet= "100";
>
>     argv[argc++] = cbcExe.c_str();
>    argv[argc++] = cbcLog.c_str();
>    argv[argc++] = cbcLogSet.c_str();
>    argv[argc++] = cbcMaxSave.c_str();
>    argv[argc++] = cbcMaxSaveSet.c_str();
>    argv[argc++] = cbcSolve.c_str();
>    argv[argc++] = cbcQuit.c_str();
>    CbcModel cbc(*osiClp);
>
>
>     CbcMain(argc, argv, cbc);
>
>
>  And from the log, I can tell there are multiple solutions.
>
>  Then, I tried to get them with:
> int nSolutions = cbc.numberSavedSolutions();
>
>  But, it says there is only 1.
>
>  When I was using cbc.branchAndBound(), this access method worked fine.
>
>  How do I get the multiple solutions back when using CbcMain?
>
>
>
>
> _______________________________________________
> Cbc mailing listCbc at list.coin-or.orghttp://list.coin-or.org/mailman/listinfo/cbc
>
>
> --
> ==================================================
> Haroldo Gambini Santos
> D.Sc, Computer Science
> Universidade Federal de Ouro Pretohttp://www.decom.ufop.br/haroldo/
>
>
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