<div dir="ltr">Thank you Mr. Bell ! Now I feel like moving in the right direction.<br>Special thanks to Peter Caspers, you are a true friend.<br><br>Best regards, Ivan.</div><div class="gmail_extra"><br><div class="gmail_quote">2015-02-27 3:49 GMT+02:00 Brad Bell <span dir="ltr"><<a href="mailto:bradbell@seanet.com" target="_blank">bradbell@seanet.com</a>></span>:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
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<div>One simple way is to use the function<br>
<a href="http://www.coin-or.org/CppAD/Doc/jacobian.xml" target="_blank">http://www.coin-or.org/CppAD/Doc/jacobian.xml</a><br>
jac = f.Jacobian(x)<br>
with the same f and different values for the vector x.<br>
<br>
In general, using the same f, without calling its constructor <br>
<a href="http://www.coin-or.org/CppAD/Doc/funconstruct.xml" target="_blank">http://www.coin-or.org/CppAD/Doc/funconstruct.xml</a><br>
or the Dependent function<br>
<a href="http://www.coin-or.org/CppAD/Doc/dependent.xml" target="_blank">http://www.coin-or.org/CppAD/Doc/dependent.xml</a><br>
uses the same tape.<br>
<br>
<br>
On 2/26/2015 8:23 AM, Иван Воронов wrote:<br>
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<div dir="ltr">Hello!<br>
<br>
<div>Please help to resolve my problem. <br>
How could I use only one tape <br>
( only one object CppAD::ADFun<double> f )<br>
in order to evaluate the derivative of function in several
points?<br>
The sequence of operation in the function does not <br>
depend on the argument values. <br>
<br>
Thanks to all who are willing to help.<br>
<br>
Regards, Ivan.</div>
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<br>
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