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I am asking you because i have a big problem. With very small
alteration in data operation time goes from 9' to 65' !!!<br>
<br>
Any recommendations on the way i solve the model? <br>
Do you think that the above times are normal for such a model?<br>
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<td>please help</td>
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<td>Wed, 03 Oct 2012 13:13:03 +0300</td>
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<th align="RIGHT" nowrap="nowrap" valign="BASELINE">From: </th>
<td>Christos <a class="moz-txt-link-rfc2396E" href="mailto:chtsolak@gmail.com"><chtsolak@gmail.com></a></td>
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<td><a class="moz-txt-link-abbreviated" href="mailto:cbc@list.coin-or.org">cbc@list.coin-or.org</a> <a class="moz-txt-link-rfc2396E" href="mailto:cbc@list.coin-or.org"><cbc@list.coin-or.org></a></td>
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Hi all,<br>
<br>
i am a student in the final phase of the Milp model which i want
to solve.<br>
<br>
So, i have a milp model<br>
columns: 46614<br>
integers: 12540 (binary)<br>
rows: 40842<br>
nonzeros:117823<br>
<br>
I tried these simple methods <br>
1.<br>
<i><small>solver1.loadProblem(numcols, numrows, start, index,
value, collb, colub, obj, rowlb, rowub);<br>
solver1.initialSolve();<br>
solver1.branchAndBound() ;</small></i><br>
2.<br>
<i><small>solver1.loadProblem(numcols, numrows, start, index,
value, collb, colub, obj, rowlb, rowub);<br>
CbcModel model(solver1);<br>
CbcMain0(model);<br>
const char * argv2[]={"DAS","-solve","-quit"}; </small></i>->
<u>i don't know what this do.</u><i><small><br>
CbcMain1(3,argv2,model); <br>
<br>
</small></i><small><big>Since i am an amateur, can you help me?<br>
What method should i use to solve the model? 1,2 or something
else?<br>
Any recommendations?<br>
<br>
The 1st takes an hour and stops.<br>
The 2nd takes either 8' or 35' depending on the data.<br>
<br>
Your help is much appreciated.<span class="HOEnZb"><font
color="#888888"><br>
<br>
Christos</font></span></big></small><br>
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